Python List vs Tuple vs Dictionary

# Input list
list1= [1,2,"python","scala"]

# index 2 is included but index 3 is excluded
print("List - " ,list1[1:3])
>> List -  [2, 'python']

# Index from backwards
print("List - " ,list1[-1])
>> List -  scala

# Multiply on string = string 
print("List - " ,list1[2]*4)
>> List -  pythonpythonpythonpython

# Check data in list
print("psython" in list1)
>> False

# iterate list
for x in list1: 
    print(x)

>>1
2
python
scala

# length of list
print("Length of list :" , len(list2))
>>  Length of list : 4

# Creating an empty Dictionary 
Dict = {}

# Creating a Dictionary 
# with dict() method 
Dict = dict({1: 'Debaditya', 2: 'Ronaldo'}) 
print("\nDictionary with the use of dict(): ") 
print(Dict) 
  
# with each item as a Pair 
Dict = dict([(1, 'Debaditya'), (2, 'Ronaldo')]) 
print("\nDictionary with each item as a pair: ") 
print(Dict) 

# find value from Dictionary
dictionary = {'Debaditya': 16, 'Ronaldo': 19}
search_value = 16
for name, value in dictionary.items(): 
    if age == search_value:
        print(name)


# find key from Dictionary
test_dict = {'Debaditya' : 1, 'Messi' : 2} 
search_key = 'Messi'

# Using list() + keys() + index() 
result = list(test_dict.keys()).index(search_key) 
print(str(result))

# Problem Statement 1
# Input : {“Gfg” : [4, 7, 5], “Best” : [8, 6, 7], “is” : [9, 3, 8]}, K = 2
# Output : [5, 7, 8]
# Explanation : The 2nd index elements are 5, 7 and 8 respectively in different keys.

list1 = []
ip = {"Gfg" : [4, 7, 5], "Best" : [8, 6, 7], "is" : [9, 3, 8]}
for name,value in ip.items():
    list1.append(value[2])
print("List - ",list1)

# Counter command is used to get frequency of values in dictionary

# Merge 2 dictionary
def Merge(dict1, dict2): 
    res = {**dict1, **dict2} 
    return res 
      
# Driver code 
dict1 = {'a': 1, 'b': 2} 
dict2 = {'d': 3, 'c': 4} 
dict3 = Merge(dict1, dict2) 
print(dict3)

>> {'b': 2, 'a': 1, 'c': 4, 'd': 3}